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The mechanical advantage of a machine which lifts a load of 20 N is 5. What is the effort applied?

A. 8.00 N
B. 4.00 N
C. 0.40 N
D. 0.25 N

Answer :

To solve this problem, we need to use the concept of mechanical advantage. Mechanical advantage (MA) is the factor by which a machine multiplies the force applied to it. It is given by the formula:

[tex]\[ \text{Mechanical Advantage (MA)} = \frac{\text{Load Force (FL)}}{\text{Effort Force (FE)}} \][/tex]

We are given:
- The mechanical advantage (MA) is 5.
- The load force (FL) lifted by the machine is 20 N.

We want to find the effort force (FE) applied to achieve this mechanical advantage.

To find the effort force, we can rearrange the formula for mechanical advantage to solve for FE:

[tex]\[ \text{Effort Force (FE)} = \frac{\text{Load Force (FL)}}{\text{Mechanical Advantage (MA)}} \][/tex]

Substitute the known values into the formula:

[tex]\[ \text{Effort Force (FE)} = \frac{20 \, \text{N}}{5} \][/tex]

Calculating the above expression gives:

[tex]\[ \text{Effort Force (FE)} = 4.0 \, \text{N} \][/tex]

So, the effort applied is 4.0 N.

The correct answer is B. 4.00 N.

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Rewritten by : Barada