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how many moles and numbers of ions of each type are present in the following aqueous solution? 76.3 ml of 1.55 m magnesium chloride:

Answer :

the number of moles of MgCl2 in the given solution is 0.1184 moles and the number of ions of MgCl2 in the given solution is 0.2368 moles.

Given, The volume of the solution = 76.3 mL The concentration of the solution = 1.55 M The formula of magnesium chloride = MgCl2 Number of moles of MgCl2 = (Concentration of MgCl2 x Volume of solution in L)Number of moles of MgCl2 = (1.55 mol/L) x (76.3 mL/1000 mL/L) = 0.1184 moles Number of ions of MgCl2 = 2 ions per one formula unit * number of formula units= 2 * 0.1184 moles = 0.2368 moles (1 mole MgCl2 contains 2 moles of ions)Therefore, the number of moles of MgCl2 in the given solution is 0.1184 moles and the number of ions of MgCl2 in the given solution is 0.2368 moles.

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