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Answer :
Final answer:
To find the new pressure at which the volume of hydrogen gas is 0.070 L, Boyle's Law is utilized. The calculation shows that the new pressure is 125.14 atm when the initial pressure is 97.5 atm and the initial volume is 90.0 mL.
Explanation:
The student's question is asking to calculate the new pressure of hydrogen gas when its volume is changed from 90.0 mL to 0.070 L, given that the initial pressure was 97.5 atm. To solve this, we can apply Boyle's Law, which states that for a given mass of gas at constant temperature, the pressure and volume are inversely proportional (P1V1 = P2V2).
Firstly, we need to convert the volume of hydrogen gas in mL to L to match the units of the final volume. So, we have:
- Initial volume (V1) = 90.0 mL = 0.0900 L
- Initial pressure (P1) = 97.5 atm
- The final volume (V2) = 0.070 L (since the problem states '070 L', we can interpret this as 0.070 L)
Applying Boyle's Law:
P2 = P1V1 / V2
P2 = (97.5 atm)(0.0900 L) / 0.070 L
P2 = 125.14 atm
So, the new pressure (P2) at which the volume of hydrogen gas would be 0.070 L is 125.14 atm.
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Answer:
0.125 atm
Explanation:
From the question,
Applying boyles law
PV = P'V'................................. Equation 1
Where P = Initial pressure, V = Initial volume, P' = Final pressure, V' = final Volume.
make P' the subject of the equation
P' = PV/V'............................. Equation 2
Given: P = 97.5 atm, V = 90 mL = 0.09 L, V' = 70 L.
Substitute these values into equation 2
P' = 97.5×0.09/70
P' = 0.125 atm
