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Answer :
The pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K is 28.2 kPa.
To calculate the pressure, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for pressure, we have: P = (nRT) / V.
Plugging in the given values:
n = 0.540 mol
V = 35.5 L
R = 8.314 J/(mol·K) (ideal gas constant)
T = 223 K
P = (0.540 mol * 8.314 J/(mol·K) * 223 K) / 35.5 L = 28.2 kPa (approximately)
Therefore, the pressure of the gas is approximately 28.2 kPa.
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