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Answer :
Thus, the standardized weight which represents the top 10% of the zucchinis from the z-table for the fisher farm is 1.28.
How to get the z scores?
If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.
[tex]Z = \dfrac{X - \mu}{\sigma}[/tex]
Here, X is sample, is μ mean and is σ standard deviation.
At the Fisher farm, the weights of zucchini squash are Normally distributed.
For the normal distribution let the value of mean is 0 and standard deviation 1. Thus,
[tex]Z = \dfrac{X - \mu}{\sigma}\\Z = \dfrac{X - 0}{1}\\Z=X[/tex]
For the top 10% of the zucchinis, the value of α is 0.9. From the table for this value the z score is,
[tex]Z=X=1.28[/tex]
Thus, the standardized weight which represents the top 10% of the zucchinis from the z-table for the fisher farm is 1.28.
Learn more about the z score here;
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