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The access code to a house's security system consists of 5 digits. How many different codes are available if each digit can be repeated?

A. 100,000
B. 45
C. 5
D. 3125
E. 32

Answer :

The number of different codes available is A)100,000.

To find the number of different codes that can be formed, we can use the concept of permutations with repetition.

In this case, we have 5 digits and each digit can be chosen from a set of 10 options (0-9).

Using the formula for permutations with repetition, which is n^k, where n is the number of options for each object and k is the number of objects, we can calculate the total number of different codes.

So, the number of different codes available is 10^5 = 100,000.

Hence Option A is correct.

Learn more about counting principle here:

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