High School

We appreciate your visit to When 1 mole of solute is dissolved in 1 kg of H₂O the boiling point of the solution becomes 100 5 degrees Celsius What is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

When 1 mole of solute is dissolved in 1 kg of H₂O, the boiling point of the solution becomes 100.5 degrees Celsius. What is the boiling point elevation constant (Kᵦ) for H₂O?

Answer :

The boiling point elevation constant (Kb) for H2O, given the increase in boiling point from 100°C to 100.5°C, is calculated to be 0.5°C kg/mol for this problem; though more generally, it's 0.51°C kg/mol.

When 1 mole of solute is dissolved in 1 kg of H2O, the boiling point of the solution increases from the normal boiling point of water (100°C) to 100.5°C. The extent to which the boiling point increases is determined by the molal boiling point elevation constant (Kb). The constant represents the elevation in boiling point experienced when one molal (1 mol/kg) of solute is dissolved in a solvent.

The formula to determine the boiling point elevation is ΔTb = Kb ⋅ m, where ΔTb is the change in boiling point and m is the molality of the solution.

Given that m equals 1 mol/kg (by definition of the problem), we can rearrange the equation to solve for Kb: ΔTb = Kb ⋅ m0.5°C = Kb ⋅ 1 mol/kg

It is now clear that Kb = 0.5°C kg/mol for H2O within the context of this specific problem.

However, the molal boiling point elevation constant for water is typically 0.51°C kg/mol.

Thanks for taking the time to read When 1 mole of solute is dissolved in 1 kg of H₂O the boiling point of the solution becomes 100 5 degrees Celsius What is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada