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Use the given limits lim x‚Üía f(x) = 9 and lim x‚Üía g(x) = ‚àí6 to determine the limit. What is the value of lim x‚Üía [4f(x)g(x)]? 1) -216 2) -24 3) 24 4) 216

Answer :

Final answer:

The limit of the expression 4f(x)g(x) as x approaches 'a' is -216, obtained by using the properties of limits and the given limits of f(x) and g(x).

Explanation:

In this question, we are given the limits of two functions as x approaches a. The limit of f(x) is 9 and the limit of g(x) is -6. We are asked to find the limit of the expression 4f(x)g(x) as x approaches a.

We know that the limit of a product of two functions is equal to the product of their individual limits. So, we can use the properties of limits to solve this question: lim x→a [4f(x)g(x)] = 4 * lim x→a f(x) * lim x→a g(x).

So, substitute the given limits to get: 4 * 9 * -6 = -216. Therefore, the limit of the expression 4f(x)g(x) as x approaches 'a' is -216.

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