High School

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chuck has a mass of 84 kg. it is a windy day and the force of the wind acting on chuck is 24 n. if chuck is standing motionless what is the sum of the forces acting on chuck?

Answer :

Final answer:

The student asked about the sum of forces acting on Chuck who is standing motionless on a windy day. Considering the downward gravitational force as 823.2 N and the sideways wind force as 24 N, the vector sum of these forces using Pythagorean theorem is 823.57 N.

Explanation:

The question asked, "Chuck has a mass of 84 kg. It is a windy day and the force of the wind acting on Chuck is 24 N. If Chuck is standing motionless what is the sum of the forces acting on Chuck?"

The two main forces acting on Chuck here are the force of gravity downwards and the force of wind, let's assume, sideways.

The force of gravity or weight (Fg) can be calculated using the equation, Fg = m * g, where m is Chuck's mass and g is the acceleration due to gravity. By substituting m = 84 kg and g = 9.8 m/s², we get Fg = 84kg * 9.8 m/s² = 823.2 N, in a downward direction.

So, Chuck experiences two forces: a downward force of gravity (823.2 N) and a sideways wind force (24 N). As these forces are not in the same direction, they can't be simply added together for a sum. But if we take their vector sum, considering the wind force being perpendicular to the force of gravity, we can use Pythagorean theorem: √[(823.2 N)² +(24 N)²] = 823.57 N. Hence, the sum of the forces acting on Chuck is 823.57 N.

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