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A roller coaster with a potential energy of [tex]$235,200 J$[/tex] sits at the top of a 30 m high hill. What is the mass of the roller coaster? (Formula: [tex]\text{PE} = mgh[/tex])

A. 800 kg
B. 7,840 kg
C. 8,000 kg
D. 78,400 kg

Answer :

Sure! Let's solve the problem step-by-step using the given formula:

We are given that the potential energy (PE) of the roller coaster is 235,200 Joules, the height (h) of the hill is 30 meters, and the acceleration due to gravity (g) is 9.8 meters per second squared. We need to find the mass (m) of the roller coaster.

The formula to calculate potential energy is:
[tex]\[ PE = m \times g \times h \][/tex]

We need to rearrange this formula to solve for mass (m):
[tex]\[ m = \frac{PE}{g \times h} \][/tex]

Now, substitute the given values into the formula:
[tex]\[ m = \frac{235,200}{9.8 \times 30} \][/tex]

Calculate the denominator:
[tex]\[ 9.8 \times 30 = 294 \][/tex]

Now, divide the potential energy by this result:
[tex]\[ m = \frac{235,200}{294} \][/tex]

This calculation gives us:
[tex]\[ m = 800 \][/tex]

Thus, the mass of the roller coaster is 800 kg. The correct answer is 800 kg.

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Rewritten by : Barada