Calcium carbonate decomposes into calcium oxide and carbon dioxide. If 224 g of calcium carbonate decomposes, how many moles of carbon dioxide gas are produced?

A. 2.24 moles of Carbon Dioxide
B. 1.12 moles of Carbon Dioxide
C. 0.04 moles of Carbon Dioxide
D. 39.3 moles of Carbon Dioxide

Question

High School

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Answer :

ishika20sam ishika20sam · Answer 1 · 2023-11-28T16:13:20-05:00

The correct answer is: 2.24 moles of carbon dioxide gas are produced when 224 g of calcium carbonate decomposes.

To determine the number of moles of carbon dioxide (CO2) gas produced when 224 g of calcium carbonate (CaCO3) decomposes, we need to use the molar mass of calcium carbonate and the stoichiometry of the balanced chemical equation.
The balanced equation for the decomposition of calcium carbonate is:CaCO3 -> CaO + CO2The molar mass of calcium carbonate (CaCO3) is calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms:
Molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 * 16.00 g/mol) (O) = 100.09 g/molNow, we can calculate the number of moles of carbon dioxide produced using the given mass of calcium carbonate:
Number of moles of CO2 = (Mass of CaCO3 / Molar mass of CaCO3)

= 224 g / 100.09 g/mol

≈ 2.24 moles of CO2

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