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Answer :
Answer:
Sum of the sequence = 132.
Step-by-step explanation:
The given sequence is 153, 139, 125,.......n terms.
Sum of the arithmetic sequence will be
S = n/2[2a + (n -1)d]
where n = number of terms
a = first term of the sequence
d = common difference
for the given sequence
a = 153
n = 22
d = 139 - 153 = -14
Therefore sum of 22 terms of the sequence will be
S = (22/2)[2×153 - (22-1)14]
= 11×[306 - 21×14]
= 11×[306 - 294] = 11×12 = 132
Sum of 22 terms of this sequence is 132.
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Rewritten by : Barada
The sum of an Arithmetic series can be calculated as:
[tex] S_{n} = \frac{n}{2}(2 a_{1}+(n-1)*d) [/tex]
n = number of terms = 22
a1 =First Term of the series = 153
d = Common Difference = 139 - 153 = -14
So, using the values, we get:
[tex] S_{22}= \frac{22}{2}(2*153+(22-1)*(-14)) \\ \\
S_{22}=132[/tex]
This means, the sum of first 22 terms of the series will be 132.
[tex] S_{n} = \frac{n}{2}(2 a_{1}+(n-1)*d) [/tex]
n = number of terms = 22
a1 =First Term of the series = 153
d = Common Difference = 139 - 153 = -14
So, using the values, we get:
[tex] S_{22}= \frac{22}{2}(2*153+(22-1)*(-14)) \\ \\
S_{22}=132[/tex]
This means, the sum of first 22 terms of the series will be 132.
