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Answer :
Final answer:
Using Ohm's law, the potential difference across a 37.9 ohm resistor with 611 mA current is found to be approximately 23.2 V, which is closest to 23.071 V.option a) 23.071 V.
Explanation:
To find the potential difference V across a resistor, we can use Ohm's law, which relates the voltage (V), current (I), and resistance (R) in a simple formula: V=IR. In this case, the current I through the 37.9 ohm resistor is given as 611 mA, which should be converted to amperes by dividing by 1000 (611 mA = 0.611 A).
Applying Ohm's law:
V = I × R
V = 0.611 A × 37.9 Ω
V = 23.1619 V
Rounding to three significant figures gives us 23.2 V, which is closest to option a) 23.071 V.
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