High School

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A toy rocket is launched vertically from ground level at time [tex]t = 0 \, \text{s}[/tex]. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 49.0 m and acquired an upward velocity of 60.0 m/s. The rocket continues to rise with insignificant air resistance in unpowered flight.

The maximum height reached by the rocket is closest to:

A) 233 m
B) 221 m
C) 209 m
D) 244 m
E) 256 m

Answer :

Final answer:

Using the kinematic formula with given values including the initial velocity of 60.0 m/s and acceleration due to gravity, the maximum height reached by the toy rocket is calculated to be closest to 244 m.

Explanation:

To find the maximum height reached by the toy rocket after engine burnout, we can use the kinematic formula which relates the final velocity (−4), initial velocity (60.0 m/s), acceleration due to gravity (-9.81 m/s2, negative since it opposes the motion), and displacement (H - 49.0 m, since 49.0 m is the height at engine burnout).

The formula we will use is −4 = v2 + 2a(s - 49.0), where −4 is the final velocity (0 m/s at the maximum height), v is the initial velocity (60.0 m/s), a is the acceleration (-9.81 m/s2), and s is the total displacement (the maximum height H). Solving for H yields H = 244 m, hence, the maximum height reached by the toy rocket is closest to 244 m, making D) 244 m the correct answer.

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