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Answer :
The amount of barium-122 remaining after 10.00 minutes, which includes 5 half-lives, will be approximately 2.50 g. This is because each half-life reduces the amount of barium-122 by half.
Barium-122 has a half-life of 2.00 minutes. This means that every 2.00 minutes, half of the barium-122 will decay.
To determine how much barium-122 will be left when the experiment begins, we need to calculate the number of half-lives that occur during the 10.00 minutes it takes to set up the experiment.
Since each half-life is 2.00 minutes, the number of half-lives that occur in 10.00 minutes is 10.00 minutes / 2.00 minutes = 5 half-lives.
Each half-life reduces the amount of barium-122 by half. So, after 1 half-life, we have 80.00 g / 2 = 40.00 g remaining. After 2 half-lives, we have 40.00 g / 2 = 20.00 g remaining.
After 3 half-lives, we have 20.00 g / 2 = 10.00 g remaining. After 4 half-lives, we have 10.00 g / 2 = 5.00 g remaining. And after 5 half-lives, we have 5.00 g / 2 = 2.50 g remaining.
Therefore, when the experiment begins, there will be approximately 2.50 g of barium-122 left.
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