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Answer :
The maximum height the toy rocket will achieve, after considering its initial acceleration and the subsequent effect of gravity, is approximately 1094.69 meters.
Calculating the Maximum Height of the Rocket
A toy rocket, launched from the ground, rises vertically with an acceleration of 20 m/s² for 6 seconds until its motor stops. The acceleration of gravity is 9.8 m/s². Disregarding any air resistance, what maximum height above the ground will the rocket achieve?
First, determine the final velocity at the end of the acceleration phase:
vf = vi + at
Given that the initial velocity (vi) is 0 (starting from rest), acceleration (a) is 20 m/s², and time (t) is 6 s:
vf = 0 + (20 m/s²)(6 s) = 120 m/s
Next, determine the height gained during the acceleration phase using the equation:
s = vit + 0.5at²
s = (0)(6 s) + 0.5(20 m/s²)(6 s)² = 0.5(20 m/s²)(36 s²) = 360 m
Now, when the motor stops, the rocket will continue to rise until its velocity decreases to 0 due to gravity. Use the following equation to find the maximum height gained during this phase:
vf² = vi² + 2ad
Here, vf = 0 m/s (at maximum height), vi = 120 m/s, and a = -9.8 m/s² (gravity acts downward):
0 = (120 m/s)² + 2(-9.8 m/s²)d
0 = 14400 - 19.6d
d = 14400 / 19.6 ≈ 734.69 m
Therefore, the total maximum height above the ground is:
Total Height = 360 m + 734.69 m ≈ 1094.69 m
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