High School

We appreciate your visit to A 20 kg crate hangs at the end of a long rope Find its acceleration magnitude and direction when the tension in the rope is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A 20-kg crate hangs at the end of a long rope. Find its acceleration (magnitude and direction) when the tension in the rope is:

a. 250 N
b. 150 N
c. 156 N
d. 196 N

Answer :

2.69ms2, −2.31ms2, −9.81ms2 and 0ms2 are acceleration (magnitude and direction) when the tension in the rope is 250 N, 150 N, 156 N and 196N respectively.

What is acceleration?

Acceleration is the rate at which an object changes its velocity over time. It is a vector quantity, which means it has both magnitude (speed) and direction. The most common unit of acceleration is meters per second squared (m/s²).

As, ΣFy=may

Using the assumption that positive means up and negative means down, we obtain:

T−mg=may

a) when T=+250:

250−(20)(9.81)=(20) ay

ay=2.69ms2

Provide the direction to your calculator. As my response was affirmative, there is an upward acceleration.

b) when T=+150:

150−(20)(9.81)=(20)ay

ay=−2.31ms2

or

ay=2.31ms2

As my solution was negative.

c) when T=0:

0−(20)(9.81)=(20)ay

ay=−9.81ms2

or

ay=9.81ms2

As my solution was negative.

d) when T=+196:

196−(20)(9.81)=(20)ay

ay=0ms2

Keep in mind that the tension and weight are equivalent while the box is not accelerating.

To learn more about acceleration visit;

https://brainly.com/question/30660316

#SPJ4

Thanks for taking the time to read A 20 kg crate hangs at the end of a long rope Find its acceleration magnitude and direction when the tension in the rope is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada