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A 3700-pF air-gap capacitor is connected to a 28-V battery.

If a piece of mica (K = 7) is placed between the plates, how much charge will flow from the battery?

Express your answer using appropriate units.

Answer :

Final answer:

The charge that will flow from the battery when a piece of mica (K = 7) is placed between the plates of the capacitor is 725200 pC.

Explanation:

To calculate the charge that will flow from the battery when a piece of mica (K = 7) is placed between the plates of the capacitor, we need to calculate the capacitance with the mica dielectric and then use it to calculate the charge.

Given:

  • Capacitance without the dielectric (C0) = 3700 pF
  • Voltage (V) = 28 V
  • Dielectric constant (K) = 7

First, we calculate the capacitance with the mica dielectric using the formula:

C = K * C0

Substituting the given values:

C = 7 * 3700 pF = 25900 pF

Next, we calculate the charge using the formula:

Q = C * V

Substituting the values:

Q = 25900 pF * 28 V = 725200 pC

Therefore, the charge that will flow from the battery when a piece of mica (K = 7) is placed between the plates of the capacitor is 725200 pC.

Learn more about charge flow in a capacitor with a dielectric material here:

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