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Calculate the final velocity of a 112 kg rugby player who is initially running at 7.95 m/s after colliding head-on with a padded goalpost and experiencing a backward force of 17,700 N for [tex]5.50 \times 10^{-2}[/tex] seconds.

Answer :

Final answer:

The final velocity of the rugby player is 16.65 m/s.

Explanation:

To calculate the final velocity, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration. In this case, the backward force is given as 17700 N and the mass of the rugby player is 112 kg. Therefore, the acceleration can be calculated by dividing the force by the mass: 17700 N / 112 kg = 158.04 m/s².

Since we have the initial velocity of the player (7.95 m/s) and the acceleration, we can use the equation of motion v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. The time is given as 5.50 x 10⁻²ˢ. Plugging in the values: v = 7.95 m/s + (158.04 m/s²) * (5.50 x 10⁻²ˢ) = 7.95 m/s + 8.70 m/s = 16.65 m/s.

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