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In a pack of wolves, there are a total of 50 wolves. The trait for a black coat (A) is dominant to the trait for a white coat (a). Given the genotype frequencies of [tex]AA = 0.23[/tex], [tex]Aa = 0.68[/tex], and [tex]aa = 0.09[/tex], complete the following questions. Assume complete dominance.

a. About how many wolves in the population have a black coat?

b. About how many wolves in the population have a black coat AND are heterozygous?

c. About how many wolves in the population have a white coat?

Answer :

Final answer:

  • Approximately 46 wolves out of 50 have a black coat.
  • Out of these, 34 are heterozygous (Aa) with black coat.
  • Aproximately 5 white-coated wolves (aa) are in the population.

Explanation:

In the given condition, both AA and Aa will have black coats because the black coat (A) trait is dominant over white coat (a) trait. This means, both AA and Aa genotypes showcase the same phenotype - a black coat. Hence,

  • a. To calculate the wolves with black coats, we add the frequencies of AA and Aa: (0.23 + 0.68)*50 = 45.5, approximately 46 wolves out of 50.
  • b. Then, for wolves who are black coated and heterozygous, we take the frequency of Aa: 0.68*50 = 34 wolves.
  • c. Finally, for whitish wolves, we look at the aa genotype: 0.09*50 = 4.5, so approximately 5 wolves out of 50.

Learn more about Genotype Frequencies here:

https://brainly.com/question/30264293

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