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Answer :
To solve the problem of finding two consecutive integers whose sum is 143, we first need to understand what consecutive integers are. Consecutive integers are numbers that follow each other in order, like 5 and 6 or 10 and 11.
Let's use the variable [tex]\( x \)[/tex] to represent the first integer. Since the integers are consecutive, the next integer is [tex]\( x + 1 \)[/tex].
According to the problem, the sum of these two consecutive integers is 143. This can be written as the equation:
[tex]\[ x + (x + 1) = 143 \][/tex]
Now, let's combine the terms on the left side of the equation:
[tex]\[ 2x + 1 = 143 \][/tex]
Next, we'll isolate [tex]\( 2x \)[/tex] by subtracting 1 from both sides:
[tex]\[ 2x = 142 \][/tex]
Now, we solve for [tex]\( x \)[/tex] by dividing both sides by 2:
[tex]\[ x = 71 \][/tex]
So, the first consecutive integer is 71. The next consecutive integer is:
[tex]\[ x + 1 = 71 + 1 = 72 \][/tex]
Therefore, the two consecutive integers whose sum is 143 are 71 and 72.
Let's use the variable [tex]\( x \)[/tex] to represent the first integer. Since the integers are consecutive, the next integer is [tex]\( x + 1 \)[/tex].
According to the problem, the sum of these two consecutive integers is 143. This can be written as the equation:
[tex]\[ x + (x + 1) = 143 \][/tex]
Now, let's combine the terms on the left side of the equation:
[tex]\[ 2x + 1 = 143 \][/tex]
Next, we'll isolate [tex]\( 2x \)[/tex] by subtracting 1 from both sides:
[tex]\[ 2x = 142 \][/tex]
Now, we solve for [tex]\( x \)[/tex] by dividing both sides by 2:
[tex]\[ x = 71 \][/tex]
So, the first consecutive integer is 71. The next consecutive integer is:
[tex]\[ x + 1 = 71 + 1 = 72 \][/tex]
Therefore, the two consecutive integers whose sum is 143 are 71 and 72.
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