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A vertical cylinder has a base area of 6 square meters. How rapidly will the fluid level inside the tank drop if we pump the fluid out at the rate of 3000 liters per minute?

A. 0.05 meters per minute
B. 0.1 meters per minute
C. 0.15 meters per minute
D. 0.2 meters per minute

Answer :

Final answer:

The rate at which the fluid level inside the tank will drop is 0.5 meters per second.

Explanation:

To solve this problem, we need to use the formula for the rate at which the fluid level is dropping. The formula is: rate of fluid level drop = rate of fluid outflow / base area of the cylinder.

The rate of fluid outflow is given as 3000 liters per minute, which can be converted to cubic meters per second by dividing by 1000. So the rate of fluid outflow is 3000/1000 = 3 cubic meters per second.

The base area of the cylinder is given as 6 sq meters. Using these values, we can calculate the rate at which the fluid level will drop: rate = 3 / 6 = 0.5 meters per second.

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Rewritten by : Barada