High School

We appreciate your visit to The weights of a sample of crates ready for shipment to Moscow Russia are in kilograms 103 97 101 106 and 103 What is the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The weights of a sample of crates ready for shipment to Moscow, Russia are (in kilograms): 103, 97, 101, 106, and 103. What is the mean deviation?

Answer :

Answer: 20

Step-by-step explanation: i'm just posting this for points dude i'm sorry

-_-

Thanks for taking the time to read The weights of a sample of crates ready for shipment to Moscow Russia are in kilograms 103 97 101 106 and 103 What is the. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

Final answer:

To find the mean deviation, calculate the sample mean, evaluate absolute differences between each weight and the mean, and then take the mean of those absolute differences. The mean deviation of the given crate weights is 2.4 kg.

Explanation:

The question asks for the calculation of the mean deviation of a set of crate weights. To calculate the mean deviation, you first need to find the mean (average) of the sample. Then, you calculate the absolute difference between each weight and the mean, and finally, average those differences to get the mean deviation.

  • Calculate the mean of the sample: (103 + 97 + 101 + 106 + 103) / 5 = 102.
  • Then, determine the absolute differences: |103 - 102| = 1, |97 - 102| = 5, |101 - 102| = 1, |106 - 102| = 4, |103 - 102| = 1.
  • Calculate the mean of these absolute differences: (1 + 5 + 1 + 4 + 1) / 5 = 2.4 kg.

The mean deviation of the crate weights is 2.4 kg.