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Answer :
Answer:
Man A: 4,000 m/250 sec = 16 m/sec
Man B: 2,000 m/120 sec = 16.67 m/sec
Man B traveled faster.
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Final answer:
After calculating the average speed for both, Man A's average speed is 16 m/s, while Man B's average speed is 16.67 m/s. Therefore, Man B traveled the fastest.
Explanation:
To determine which man traveled the fastest, we need to calculate the average speed of both Man A and Man B. The average speed is calculated by dividing the distance traveled by the time taken to travel that distance.
Calculating Man A's Average Speed:
Distance = 4000 meters
Time = 250 seconds
Average Speed = Distance ÷ Time
Average Speed of Man A = 4000 m ÷ 250 s = 16 m/s
Calculating Man B's Average Speed:
Distance = 2000 meters
Time = 120 seconds
Average Speed = Distance ÷ Time
Average Speed of Man B = 2000 m ÷ 120 s = 16.67 m/s
Since Man B has a higher average speed than Man A, Man B traveled the fastest.
