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Answer :
For the trait for 'black feet in ferrets' is a recessive trait encoded for by "f". white feet is encoded for by a dominant allele encoded for by the letter "f" the sum of the frequencies for f and f all alleles must equal 1.
Let's calculate the frequency of the f allele (p):
The 360 ferrets with black feet are homozygous recessive (ff), so the frequency of the f allele is sqrt(360/1000) = 0.6
The 480 heterozygous ferrets (Ff) have one f allele each, so the frequency of the f allele is 480/1000 x 0.5 = 0.24
The 160 homozygous dominant ferrets (FF) have no f alleles, so the frequency of the f allele is 0.
The sum of the frequencies of f and F is 1, so the frequency of the F allele (q) is:
q = 1 - p = 1 - 0.6 = 0.4
Therefore, the answer is (a) f = 0.4 and f = 0.6.
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