We appreciate your visit to How many moles of tex Al CN 3 tex are in 221 g of the compound. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The number of moles of Al(CN)3 in 221 g of the compound is approximately 2.10 moles, calculated using the molar mass of Al(CN)3 which is 105.04 g/mol.
Explanation:
To calculate the number of moles of Al(CN)3 in 221 g of the compound, we need to know the molar mass of Al(CN)3. Each molecule of Al(CN)3 contains one aluminum atom (Al) and three cyanide groups (CN). The atomic mass of aluminum (Al) is approximately 26.98 g/mol, and the atomic mass of a cyanide group (CN) is about 26.02 g/mol (12.01 for carbon and 14.01 for nitrogen). Therefore, the molar mass of one mole of Al(CN)3 is 26.98 g/mol for Al + (3 × 26.02 g/mol for CN) = 105.04 g/mol for Al(CN)3.
Using this molar mass, we can set up a conversion from grams to moles:
- Divide the mass of Al(CN)3 by its molar mass: 221 g / 105.04 g/mol.
- This calculation gives us the number of moles: 221 g / 105.04 g/mol ≈ 2.10 moles of Al(CN)3.
Thanks for taking the time to read How many moles of tex Al CN 3 tex are in 221 g of the compound. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
