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Answer :
Final answer:
The mean deviation of the weights of crates ready for shipment to Moscow is calculated by first finding the mean of the weights, then the absolute deviations from the mean, and finally, the mean of those absolute deviations, which is 2.4 kilograms.
Explanation:
The weights of a sample of crates ready for shipment to Moscow, Russia are (in kilograms): 103, 97, 101, 106, and 103. The question asks for the calculation of the mean deviation. To find the mean deviation, follow these steps:
- Calculate the mean (average) of the sample.
- Find the absolute deviation of each value from the mean.
- Calculate the mean of these absolute deviations to get the mean deviation.
Mean = (103 + 97 + 101 + 106 + 103) / 5 = 510 / 5 = 102 kg
|103 - 102| = 1
|97 - 102| = 5
|101 - 102| = 1
|106 - 102| = 4
|103 - 102| = 1
Mean deviation = (1 + 5 + 1 + 4 + 1) / 5 = 12 / 5 = 2.4 kg. The mean deviation of the crate weights is 2.4 kilograms.
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Answer:
Step-by-step explanation:
To calculate the mean deviation of the weights of the sample crates, we first need to find the mean of the data set. The mean is calculated by adding up all the values and then dividing by the total number of values.
Given weights: 103, 97, 101, 106, and 103
Mean = (103 + 97 + 101 + 106 + 103) / 5 = 510 / 5 = 102
Next, we calculate the deviation of each value from the mean:
Weight Deviation from Mean
103 1
97 -5
101 -1
106 4
103 1
Now, we find the absolute deviation for each value by taking the absolute value of each deviation:
Weight Deviation from Mean Absolute Deviation
103 1 1
97 -5 5
101 -1 1
106 4 4
103 1 1
The mean deviation is calculated by finding the average of these absolute deviations:
Mean Deviation = (1 + 5 + 1 + 4 + 1) / 5 = 2.4
Therefore, the mean deviation of the weights of the sample crates is 2.4 kilograms.
