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Answer :
Final answer:
The 0.9% 250cc normal saline solution contains 38.46 meq of Na+. This is calculated based on the molar mass of NaCl and the assumption of complete dissociation in water.
Explanation:
In a 0.9% normal salty solution, there's 9g of sodium chloride (NaCl) dissolved in 1 Liter (1000 cc) of water, assuming complete dissociation. Considering, 250cc is a quarter of 1000cc, so 250cc 0.9% saline solution contains 2.25g of NaCl. The molar mass of NaCl is 58.5g/mol which provides 0.038 moles of NaCl in 250cc. As NaCl breaks into Na+ and Cl-, each mole of NaCl will provide 1 mole of Na+. Hence, in 0.038 moles of NaCl, we have 0.038 moles or 38.46 meq (Milliequivalents) of Na+ (since 1 mole equals 1000 meq). So, the answer is d. 38.46 meq.
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