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A 750 kg car accelerates from rest to 15 m/s in 12.0 s. The average power given out by the engine is:

A) 6 kJ
B) 112 J
C) 168 kJ
D) 84 kJ

Answer :

The average power given out by the engine is approximately 14.0 kJ.(Non of the Options)

To calculate the average power given out by the engine, we first need to determine the work done by the engine to accelerate the car from rest to 15 m/s in 12.0 seconds. We can use the formula for work:

Work = Force × Distance

Since the force exerted by the engine causes the car to accelerate, we use the formula for force:

Force = Mass × Acceleration

Given that the car's mass m = 750 kg and its acceleration a = Δv / Δt = 15 m/s / 12.0 s, we can calculate the force. Then, we use the formula for work to find the total work done by the engine.

Next, we use the formula for power:

Power = Work / Time

Given that the time taken for the acceleration is Δt = 12.0 seconds, we can divide the total work by this time to find the average power given out by the engine.

Now, let's calculate:

Acceleration = Δv / Δt = 15 m/s / 12.0 s = 1.25 m/s²

Force = m × a = 750 kg × 1.25 m/s² = 937.5 N

Work = Force × Distance = 937.5 N × 15 m = 14062.5 J

Power = Work / Time = 14062.5 J / 12.0 s = 1171.875 W = 1.17 kW

Therefore, the average power given out by the engine is approximately 1.17 kW. To convert this to kilojoules (kJ), we multiply by the time duration:

Power = 1.17 kW × 12.0 s = 14.04 kJ ≈ 14 kJ

Thus, the average power given out by the engine is approximately 14.0 kJ.(Non of the Options)

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