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Answer :
After thorough calculation, we get, the velocity of the goalie after catching the hockey puck is 0.270 m/s, when a 0.105-kg hockey puck moving at 26 m/s is caught and held by a 67-kg goalie at rest.
Given data A 0.105-kg hockey puck moving at 26 m/s is caught and held by a 67-kg goalie at rest.
The mass of the hockey puck is m1 = 0.105 kg.
The mass of the goalie is m2 = 67 kg.
The velocity of the hockey puck is v1 = 26 m/s.
Let's assume the velocity of the goalie after catching the hockey puck as v2.
Therefore, we have the equationm1v1 + m2u = (m1 + m2)v2, where u is the initial velocity of the goalie and v2 is the velocity of the goalie after catching the hockey puck.
We get 0.105 × 26 + 67 × 0 = (0.105 + 67)v2v2 = 0.270 m/s.
Therefore, the velocity of the goalie after catching the hockey puck is 0.270 m/s.
Read more about The velocity of the goalie.
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