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At 46ºC and 0.880 atm pressure, a gas occupies a volume of 0.600 L. How many liters will it occupy at 0ºC and 0.205 atm?

Answer :

Final answer:

To find the new volume, you can use the ideal gas law equation PV = nRT and solve for V2. Plugging in the given values, the gas will occupy 0.149 liters at 0ºC and 0.205 atm.

Explanation:

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. To find the new volume, we can use the equation PV = nRT and solve for V2. Rearranging the equation, we have V2 = (P2 x V1 x T1) / (P1 x T2).

Plugging in the given values, we have V2 = (0.205 atm x 0.600 L x 319 K) / (0.880 atm x 273 K). Solving this equation gives us V2 = 0.149 L. Therefore, the gas will occupy 0.149 liters at 0ºC and 0.205 atm.

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