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Take East as the positive direction. An 89 kg fisherman jumps from a dock into a 135 kg rowboat at rest on the west side of the dock. If the velocity of the fisherman is 5.2 m/s to the west as he leaves the dock, what is the final velocity of the fisherman and the boat?

Answer in units of m/s.

Answer :

The final velocity of the fisherman and the boat is 2.06 m/sec.

What is meant by velocity?

  • The directional speed of an item in motion, as measured by a specific unit of time and viewed from a certain point of reference, is what is referred to as velocity.
  • The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The metre per second (m/s) is the accepted unit of velocity magnitude (also known as speed).
  • The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).
  • Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, velocity is a vector, whereas speed is a scalar number.

Given data :

We have given mass of the fisherman [tex]m_{1}[/tex] = 89 kg

Velocity of fisherman v = - 5.2 m/sec ( As east direction is positive direction )

Mass of the rowboat [tex]m_{2}[/tex] = 135 kg

As the rowboat is at rest so [tex]v_{2}[/tex] = 0 m/sec

Now according to conservation of momentum

[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex][tex]v_{2}[/tex] = ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] ) v

89 x 5.2 + 135 x 0 = ( 89 + 135 ) x v

462.8 + 0 = 224 x v

v = 462.8/ 224 = 2.06 m/sec

Learn more about velocity refer to ;

https://brainly.com/question/25749514

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