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Answer :
Use the formula for the conditional probability:
[tex] Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr B}. [/tex]
Consider such events
A - a senior takes the bus to school every day;
B - a senior has a driver’s license,
then
[tex] Pr(A\cap B)=0.14 [/tex],
[tex] Pr(B)=0.84 [/tex]
and
[tex] Pr(A|B)=\dfrac{0.14}{0.84} =\dfrac{1}{6}\approx 0.16666. [/tex]
In percent this is nearly 17%.
Answer: correct choice is B.
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