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Answer :
The answer is [tex]4 x^{2} +6x-5[/tex]
[tex] \frac{28 x^{3} +42 x^{2} -35x}{7x} = \frac{28 x^{3} }{7x} + \frac{42 x^{2} }{7x} - \frac{35x}{7x} =4 x^{2} +6x-5[/tex]
[tex] \frac{28 x^{3} +42 x^{2} -35x}{7x} = \frac{28 x^{3} }{7x} + \frac{42 x^{2} }{7x} - \frac{35x}{7x} =4 x^{2} +6x-5[/tex]
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Rewritten by : Barada
(28x³ + 42x²– 35x)/(7x) = 28x³/(7x) + 42x²/(7x) + 35x/(7x) = 4x² + 6x + 5
