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A concave mirror with a radius of curvature of 1.64 m is placed behind a chess piece, which is a distance of 0.271 m from the reflecting side of the mirror along its principal axis. What is the position of the image?

Answer in units of meters.

Answer :

The position of the image is approximately 0.2468 m from the reflecting side of the mirror along its principal axis.

The position of the image formed by the concave mirror can be determined using the mirror formula: 1/f = 1/v - 1/u, where f is the focal length of the mirror, v is the distance of the image from the mirror, and u is the distance of the object from the mirror.

Given that the radius of curvature of the mirror is 1.64 m, the focal length is half of the radius, so f = 0.82 m.

The distance of the object from the mirror is u = 0.271 m.

Plugging these values into the mirror formula, we can solve for the distance of the image from the mirror, v.

1/0.82 = 1/v - 1/0.271

Simplifying the equation, we get:

0.3683 = 1/v - 3.6868

Rearranging the equation, we find:

1/v = 3.6868 + 0.3683

1/v = 4.0551

v = 1/4.0551

v ≈ 0.2468 m

Therefore, the position of the image is approximately 0.2468 m from the reflecting side of the mirror along its principal axis.

To know more about principal axis visit:-

https://brainly.com/question/3806629

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