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Answer :
Final answer:
The moment of inertia of the barbell about the central perpendicular axis is 80 kg·m².
Explanation:
The moment of inertia of the barbell about the central perpendicular axis can be calculated by considering the two masses at the ends of the uniform rod. Each mass will contribute to the moment of inertia, given by I = mR², where m is the mass of each mass and R is the distance of the mass from the axis. In this case, since each mass is 20 kg and the rod has a length of 2.0 m, the moment of inertia is calculated as follows:
I₁ = (20 kg)(1.0 m)² + (20 kg)(1.0 m)² = 40 kg·m² + 40 kg·m² = 80 kg·m²
Therefore, the moment of inertia of the barbell about the central perpendicular axis is 80 kg·m².
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