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Answer :
Final answer:
The mathematics problem requires setting up a system of equations to solve for the number of bucks and does in the pasture. By doing so, you find that there are 3 bucks in the pasture.
Explanation:
The subject of this question is a typical algebra problem. We know that there are 19 deer in total in the front pasture. Also, it is given that there are seven more does (female deer) than triple the number of bucks (male deer).
We can write a system of equations to illustrate this scenario:
- B + D = 19
- D = 3B + 7
Where B represents the number of bucks, and D represents the number of does.
Next, we substitute equation 2 into equation 1:
B + (3B + 7) = 19
Solving for B, we simplify this to get 4B + 7 = 19.
Subtracting 7 from each side, we get 4B = 12. Dividing both sides by 4, we arrive at B = 3.
So, there are 3 bucks in the front pasture.
Learn more about System of Equations here:
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