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Answer :
There are two types of tickets,
Senior citizens ticket and child ticket
Let seniors citizen ticket be x and
Child ticket be y.
For the first day,
3x+y=38 ….(1)
For the second day,
3x+2y=52 ……(2)
Now solving (1) and (2),
By subtracting (1) from (2),
y=52-38
y= 14
By plugging the value of your in either of the two equations,
We get,
x=8
The cost of a senior citizen ticket is $8
The cost of a child ticket is $14
Senior citizens ticket and child ticket
Let seniors citizen ticket be x and
Child ticket be y.
For the first day,
3x+y=38 ….(1)
For the second day,
3x+2y=52 ……(2)
Now solving (1) and (2),
By subtracting (1) from (2),
y=52-38
y= 14
By plugging the value of your in either of the two equations,
We get,
x=8
The cost of a senior citizen ticket is $8
The cost of a child ticket is $14
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Final answer:
The price of a senior citizen ticket is $8 and the price of a child ticket is $14.
Explanation:
Let's assume the price of a senior citizen ticket is x dollars and the price of a child ticket is y dollars.
On the first day of ticket sales, the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. This can be represented by the equation 3x + y = 38.
On the second day, the school sold 3 senior citizen tickets and 2 child tickets for a total of $52. This can be represented by the equation 3x + 2y = 52.
To find the price of a senior citizen ticket and the price of a child ticket, we need to solve this system of equations.
Multiplying the first equation by 2, we get 6x + 2y = 76. Subtracting the second equation from this, we get 3x = 24. So, x = 8.
Substituting the value of x into the first equation, we get 3(8) + y = 38. Solving for y, we get y = 14.
Therefore, the price of a senior citizen ticket is $8 and the price of a child ticket is $14.
