We appreciate your visit to How many liters of water must be added to 98 3 grams of NaCl to make a 2 18 M solution. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer
0.77 liters of water
Step by step solved:
To calculate how many liters of water must be added to 98.3 grams of NaCl to make a 2.18 solution, we need to use the formula:
C = n/V
where C is the concentration of the solution in units of moles per liter (M), n is the number of moles of the solute (in this case, NaCl), and V is the volume of the solution in liters.
We are given the mass of NaCl and the desired concentration of the solution, so we can first calculate the number of moles of NaCl that we need:
n = m/M
where m is the mass of NaCl and M is the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol.
n = 98.3 g / 58.44 g/mol ≈ 1.68 mol
Now we can use the formula for concentration to find the volume of the solution:
C = n/V
2.18 mol/L = 1.68 mol / V
V = 1.68 mol / 2.18 mol/L ≈ 0.77 L
So, we need to add 0.77 liters of water to 98.3 grams of NaCl to make a 2.18 solution.
0.77 liters of water
Step by step solved:
To calculate how many liters of water must be added to 98.3 grams of NaCl to make a 2.18 solution, we need to use the formula:
C = n/V
where C is the concentration of the solution in units of moles per liter (M), n is the number of moles of the solute (in this case, NaCl), and V is the volume of the solution in liters.
We are given the mass of NaCl and the desired concentration of the solution, so we can first calculate the number of moles of NaCl that we need:
n = m/M
where m is the mass of NaCl and M is the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol.
n = 98.3 g / 58.44 g/mol ≈ 1.68 mol
Now we can use the formula for concentration to find the volume of the solution:
C = n/V
2.18 mol/L = 1.68 mol / V
V = 1.68 mol / 2.18 mol/L ≈ 0.77 L
So, we need to add 0.77 liters of water to 98.3 grams of NaCl to make a 2.18 solution.
Thanks for taking the time to read How many liters of water must be added to 98 3 grams of NaCl to make a 2 18 M solution. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
Answer:
83.22L
Explanation:
To solve this problem, we need to use the formula for calculating the concentration of a solution:
concentration = (mass of solute / mass of solvent + mass of solute) x 100
In this case, we know the concentration (2.18), the mass of the solute (98.3 g NaCl), and we want to find the mass of the solvent (water) needed to achieve this concentration.
Let's start by rearranging the formula to solve for the mass of the solvent:
mass of solvent = mass of solute / (concentration / 100 - 1)
Plugging in the values we know:
mass of solvent = 98.3 g / (2.18 / 100 - 1)
mass of solvent = 98.3 g / 1.18
mass of solvent = 83.22 g
So we need 83.22 grams of water to make the solution.
Now we can convert this mass to volume using the density of water, which is 1 g/mL:
volume of water = mass of water / density of water
volume of water = 83.22 g / 1 g/mL
volume of water = 83.22 mL
Therefore, we need to add 83.22 mL of water to 98.3 grams of NaCl to make a 2.18% solution.
