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What is the ratio of power outputs by two microwave ovens having frequencies of 950 MHz and 2560 MHz, if they emit the same number of photons per second?

A. 2.69
B. 1; 2.69
C. 1.69; 1
D. 1; 1.69

Answer :

Final answer:

The ratio of power outputs by two microwave ovens at 950 and 2560 MHz, emitting the same number of photons per second, is approximately 1 to 2.69.

Explanation:

The ratio of power outputs by two microwave ovens with frequencies of 950 and 2560 MHz, given that they emit the same number of photons per second, can be found by using the formula for energy of a photon, E = hf, where h is Planck's constant and f is the frequency. Since they emit the same number of photons, the power, which is energy per time, is directly proportional to the frequency.

To find the ratio of the power outputs (P1/P2), we can compare the frequencies directly because the number of photons emitted per second is the same:

  • For the first oven at 950 MHz, let's call the power output P1.
  • For the second oven at 2560 MHz, let's call the power output P2.

The ratio is therefore P1/P2 = f1/f2 = 950 MHz / 2560 MHz = 0.3711.

To compare as a ratio, P2 is to P1 as 1 is to 0.3711 or inversely 1 : 1/0.3711, which equals approximately 1 : 2.69.

The correct answer is (b) 1; 2.69.

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