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The weights of adult men in a hypothetical population are approximately normally distributed with a mean of 175 lbs and a standard deviation of 15 lbs. If Harvey is at the 90th percentile in weight for adult men, his weight, in pounds, is closest to:

A. 192 pounds
B. 194 pounds
C. 196 pounds
D. 200 pounds
E. 205 pounds

Answer :

Final answer:

To find Harvey's weight at the 90th percentile, a z-score is used with the normal distribution. The weight corresponding to this percentile is calculated to be approximately 194 pounds. Hence, option B is the most likely answer.

Explanation:

In order to determine Harvey's weight at the 90th percentile, we would need to use the concept of z-scores in the normal distribution. The z-score for the 90th percentile is approximately 1.28.

We can calculate the weight corresponding to Harvey's percentile using the formula: weight = mean + z*standard deviation.

Substituting in given values, we get weight = 175 + 1.28*15. This calculation yields a weight of approximately 194 pounds, so option B would be closest to this value.

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