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Find the volume of the triangular pyramid to the nearest whole number.

A) 340 in3

B) 567 in3

C) 850 in3

D) 1,133 in3

Find the volume of the triangular pyramid to the nearest whole number A 340 in3 B 567 in3 C 850 in3 D 1 133 in3

Answer :

The area of a triangular pyramid is given by [tex] V =\frac{1}{3} Ah[/tex]

Where A = area of the base, and h = height.


Knowing this, the area of your figure can be calculated by:

[tex] \frac{1}{3} * ( \frac{17*10}{2} ) *20[/tex]
=
[tex] \frac{1}{3} * 85 *20[/tex]
=
[tex] \frac{1}{3} * 1700[/tex]
=
[tex]566.(6)[/tex] reoccuring.

Or 567in^3

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Rewritten by : Barada

V = 1/3AH...where A is the the area of triangle base and H is height

lets do area of base....area of triangle is (HB)/2...so the area of the base is
(10* 17) / 2 = 170/2 = 85....so in the main formula, A = 85

V = 1/3AH......A = 85 and H = 20
V = 1/3(85 * 20)
V = 1/3(1700)
V = 1700/3
V = 566.6 rounds to 567 in^3 <==