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In a \(_{41}^{93}\text{Nb}\) nucleus, how many protons, neutrons, and electrons are found there?

1) 93, 41, 93
2) 41, 52, 93
3) 41, 52, 0
4) 52, 41, 41
5) 41, 52, 41

Answer :

The accurate combination is option 5) 41,52,41.

1. Identify the nucleus: Given [tex]\(^{93}_{41}\text{Nb}\)[/tex], we have the element niobium (Nb) with an atomic number of 41 and a mass number of 93.

2. Determine the number of protons: The atomic number (subscript) represents the number of protons in the nucleus. In this case, it's 41, indicating that there are 41 protons.

3. Calculate the number of neutrons: Neutrons can be found by subtracting the atomic number from the mass number.

So, 93 - 41 = 52, giving us 52 neutrons.

4. Find the number of electrons: In a neutral atom, the number of electrons is equal to the number of protons.

Therefore, there are also 41 electrons.

So, the step-by-step calculation yields:

- Protons: 41

- Neutrons: 52

- Electrons: 41

This result matches with option 5) 41,52,41.

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