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Answer :
Final answer:
The second order partial derivative of F(x,y) = x³+ x²y³ - 2y² with respect to x at point (2,1) is 14.
Explanation:
In order to find the second order partial derivative of F(x,y) with respect to x, we first need to find the first order derivative. Given F(x,y) = x³+ x²y³ - 2y², the first order derivative with respect to x is Fx = 3x² + 2xy³.
Next, we take the derivative of Fx with respect to x again to find the second order partial derivative. The result is
Fxy= 6x + 2y³.
Finally, in order to evaluate at the point (2,1), we plug these values into Fxy. This results in
Fxy(2,1) = 6(2) + 2(1)³
Fxy(2,1) = 12 + 2
Fxy(2,1) = 14.
So, the correct answer is: a. 14
Complete question:
The second order partial derivative of F(x,y) = x³+ x²y³-2y² w.r.t. x at (2,1) is
O a. 14
O b. 12
О с. 0
O d. 8
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