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Two cars leave towns 950 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 5 hours, what is the rate of the slower car?

Answer :

Final answer:

The rate of the slower car is 88 km/h.

Explanation:

To find the rate of the slower car, we need to set up an equation using the formula distance = rate x time. Let's call the rate of the slower car r km/h. The rate of the faster car will then be r + 14 km/h. Since they meet in 5 hours, we can set up the equation:

(r km/h)(5 hours) + (r + 14 km/h)(5 hours) = 950 km

Simplifying the equation, we get:

5r + 5(r + 14) = 950

5r + 5r + 70 = 950

10r + 70 = 950

10r = 880

r = 88

Therefore, the rate of the slower car is 88 km/h.

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