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Answer :
The magnitude of the frictional force of the box is 65 N
From the question given above, the following data were obtained:
- Mass (m) = 25 Kg
- Force applied (Fₐ) = 135 N
- Net force (Fₙ) = 70 N
- Frictional force (Fբ) =?
The frictional force acting on the box can be obtained as follow:
Fₙ = Fₐ – Fբ
70 = 135 – Fբ
Collect like terms
70 – 135 = – Fբ
–65 = –Fբ
Multiply through by –1
Fբ = 65 N
Thus, the frictional force of the box is 65 N
Learn more on Frictional force: https://brainly.com/question/25767576
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