Answer :

Final answer:

To determine the temperature of Boiling Temperatures water corresponding to a steam gauge reading of 95.6 psig, consult a steam table or use the appropriate steam table formula for the given pressure.

Explanation:

To find the temperature of the boiling water in a boiler where the steam gauge reads 95.6 psig, we need to convert that pressure into an applicable unit and apply the Clausius-Clapeyron equation. This is a physics equation used to describe the relationship between the temperature and pressure at the boiling point of a substance.

First, remember that 1 psig is approximately equal to 6.895 kPa. So 95.6 psig would be about 660 kPa. We then substitute the values T₁ = 80.1 °C = 353.3 K, P₁ = 101.3 kPa, ∆Hvap = 30.8 kJ/mol for boiling at sea level, our P₂ = 660 kPa, into the rearranged Clausius-Clapeyron equation to solve for the new boiling temperature (T₂).

This provides a method to calculate the temperature of the boiling water under the given pressure.

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