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What is the remainder in the synthetic division problem below?

[tex]
1 \quad 1 \quad 2 \quad -3 \quad 2
[/tex]

A. 3
B. 5
C. 2
D. 4

Answer :

To solve the synthetic division problem and find the remainder, we need to follow these steps:

1. Identify the Polynomial and Divisor:
We have a polynomial with coefficients [tex]\(1, 2, -3, 2\)[/tex]. This represents the polynomial [tex]\(x^3 + 2x^2 - 3x + 2\)[/tex].
We are dividing this polynomial by [tex]\(x + 1\)[/tex], which means the divisor [tex]\(x - (-1) = x + 1\)[/tex].

2. Set Up for Synthetic Division:
Since we are dividing by [tex]\(x + 1\)[/tex], our divisor is [tex]\(-1\)[/tex]. We use [tex]\(-1\)[/tex] in our synthetic division process.

3. Perform the Synthetic Division:
Write down the coefficients: [tex]\(1, 2, -3, 2\)[/tex].

- Start by bringing down the first coefficient (1) as it is.
- Multiply this number by the divisor [tex]\(-1\)[/tex], and write the result underneath the second coefficient (2).
- Add this result to the second coefficient to get the new value for the next step.
- Repeat this process for each coefficient.

Steps in detail:
- Bring down the 1:
- Write 1 below the line.

- Multiply 1 by [tex]\(-1\)[/tex] and add to 2:
[tex]\[
\text{First step: } 1 \times (-1) + 2 = 1
\][/tex]

- Multiply 1 by [tex]\(-1\)[/tex] and add to -3:
[tex]\[
\text{Second step: } 1 \times (-1) + (-3) = -4
\][/tex]

- Multiply [tex]\(-4\)[/tex] by [tex]\(-1\)[/tex] and add to 2:
[tex]\[
\text{Third step: } (-4) \times (-1) + 2 = 6
\][/tex]

4. Determine the Remainder:
The last number we obtain after processing all the coefficients is the remainder. In this case, the remainder is 6.

Thus, the remainder of the synthetic division is [tex]\(6\)[/tex]. The correct answer is not listed among the given options, but this number is obtained from the process.

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