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Answer :
The rate of heat transfer by convection from the tube to the air is 53.091 kW (option c).
To determine the rate of heat transfer by convection from the tube to the air, we need to use the equation
Q=hA (Ts-Ta),
where Q is the rate of heat transfer, h is the heat transfer coefficient, A is the surface area of the tube, Ts is the temperature of the outer surface of the tube and Ta is the temperature of the air in the room.
First, we need to find the surface area of the tube. The diameter is given as 13 cm, so the radius is 6.5 cm. The surface area of a cylinder is 2πrh+2πr², where r is the radius and h is the length.
Therefore, the surface area of the tube is 2π(6.5 cm)(100 m) + 2π(6.5 cm)²= 4,370.7 m².
Substituting the given values in the equation Q=hA (Ts-Ta),
we get Q = (13 W/m².K)(4,370.7 m²)(110-10)°C = 53,091 kW.
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