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Answer :
Certainly! Let's solve the equation [tex]\(\log(x) = 2\)[/tex].
1. The equation [tex]\(\log(x) = 2\)[/tex] means we are using a common logarithm, which is base 10. So, it can be stated as [tex]\(\log_{10}(x) = 2\)[/tex].
2. To solve for [tex]\(x\)[/tex], we need to convert the logarithmic equation into an exponential form. The equivalent exponential form of [tex]\(\log_{10}(x) = 2\)[/tex] is:
[tex]\[
x = 10^2
\][/tex]
3. Now, calculate [tex]\(10^2\)[/tex]. This means multiplying 10 by itself:
[tex]\[
10 \times 10 = 100
\][/tex]
So, the value of [tex]\(x\)[/tex] is 100. Therefore, the solution to the equation [tex]\(\log(x) = 2\)[/tex] is [tex]\(x = 100\)[/tex].
1. The equation [tex]\(\log(x) = 2\)[/tex] means we are using a common logarithm, which is base 10. So, it can be stated as [tex]\(\log_{10}(x) = 2\)[/tex].
2. To solve for [tex]\(x\)[/tex], we need to convert the logarithmic equation into an exponential form. The equivalent exponential form of [tex]\(\log_{10}(x) = 2\)[/tex] is:
[tex]\[
x = 10^2
\][/tex]
3. Now, calculate [tex]\(10^2\)[/tex]. This means multiplying 10 by itself:
[tex]\[
10 \times 10 = 100
\][/tex]
So, the value of [tex]\(x\)[/tex] is 100. Therefore, the solution to the equation [tex]\(\log(x) = 2\)[/tex] is [tex]\(x = 100\)[/tex].
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